Kamis, 10 Oktober 2013

himpunan


Jika P,Q,R adalah himpunan ,buktikan bahwa
(PᴗQ)ᴖ(PcᴖR)c = Pᴗ(QcᴗR)c
Pembuktian
Pembuktian 1
Diketahui :
P={1,3,4,6,7}                      S={1,2,3,4,5,6,7,8,10,11,13}
Q={2,3,4,5,8,10}               
R={1,6,10,11,13}
Jawab :
PᴗQ                       ={1,2,3,4,5,6,7,8,9,10}                    QC                           ={1,6,7,11,13}
PC                                          ={1,2,3,4,5,6,7,8}                              QCᴗR                      ={1,6,7,10,11,13}
PCᴖR                      ={10,11,13}                                         (QCᴗR)C                         ={2,3,4,5,8}
(PCᴖR)C                 ={1,2,3,4,5,6,7,8}                             
(PᴗQ)ᴖ(PCᴖR)C            ={1,2,3,4,5,6,7,8}                    Pᴗ(QCᴗR)C               ={1,2,3,4,5,6,7,8}
Pembuktian 2
Diketahui :
P={a,b,d,h,i,k}                   S={a,b,c,d,e,f,g,h,i,j,k}
Q={b,c,e,f,h}
R={c,d,g,h,j}
Jawab :
PᴗQ                       ={a,b,c,d,e,f,h,i,k}                                           Qc                                         ={a,d,g,i,j,k}      
Pc                                          ={c,f,g,j}                                                               QcᴗR                      ={a,c,d,g,h,I,j,k}
PcᴖR                       ={c,g,j}                                                                  (QcᴗR)c                          ={b,e,f}
(PcᴖR)c                           ={a,b,d,e,f,h,i,k}                                                              
 (PᴗQ)ᴖ(PcᴖR)c    ={a,b,d,e,f,h,i,k}                                                              Pᴗ(QcᴗR)c                  ={a,b,d,e,f,h,I,k}

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